zip

源码
​https://github.com/ddzy/ts-utility-plugins/tree/master/src/ddzy/utility/array/zip​
说明
创建一个分组元素的数组, 数组的第一个元素包含所有给定数组的第一个元素, 数组的第二个元素包含所有给定数组的第二个元素, 以此类推. 打包后的数组的长度等于源二维数组的最大长度的项
用法
zip.use.ts
zip.test.ts
zip.use.ts
import { zip } from "./ddzy/utility/array/zip";
​
// ? 数字数组
const s1 = [[1, 2, 3], [4, 5, 6], [7, 8, 9, 10, 11]];
const p1 = zip<number>(...s1);
console.log(p1);
​
// ? 混合数组
const s2 = [
  [100, 200, 300],
  [false, true],
  [[], { name: 'duanzhaoyang', age: 21 }],
];
const p2 = zip<any>(...s2);
console.log(p2);
zip.test.ts
import { zip } from "../../utility/array/zip";
​
describe('Method zip tests...', () => {
  test('zip should return the zipped array correctly when receive an array composed of number', () => {
    const received = [
      [1, 2, 3],
      [4, 5, 6],
      [7, 8, 9, 10, 11],
    ];
    const expected = [
      [1, 4, 7],
      [2, 5, 8],
      [3, 6, 9],
      [10],
      [11]
    ];
​
    const result = zip<number>(...received);
​
    expect(result.length).toBe(expected.length);
​
    result.forEach((outerV, outerI) => {
      outerV.forEach((innerV, innerI) => {
        expect(innerV).toBe(expected[outerI][innerI]);
      });
    });
  });
​
  test('zip should return the zipped array correctly when receive an mixed array', () => {
    const arr1: any[] = [];
    const obj1 = {
      name: 'duanzhaoyang',
      age: 21,
    }
    const func1 = function () { };
​
    const received = [
      [998, 899, 989, 898],
      [false, true],
      [arr1, obj1],
      [func1]
    ];
    const expected = [
      [998, false, arr1, func1],
      [899, true, obj1],
      [989],
      [898],
    ];
​
    const result = zip<any>(...received);
​
    expect(result.length).toBe(expected.length);
​
    result.forEach((outerV, outerI) => {
      outerV.forEach((innerV, innerI) => {
        expect(innerV).toBe(expected[outerI][innerI]);
      });
    });
  });
});
pullAll
_join
Last updated 7 months ago