isNull
说明
 判断是否为严格的null
源码
https://github.com/ddzy/ts-utility-plugins/tree/master/src/ddzy/utility/others/isNull
用法
import { isNull } from "util";
describe('isNull', () => {
  test('isNull should return `false` if received a non null value', () => {
    const received = [
      0,
      '',
      undefined,
      {},
      [],
      function () { },
    ];
    for (const v of received) {
      expect(isNull(v)).toBeFalsy();
    }
  });
  test('isNull should return `true` if received a null value', () => {
    const received = [
      null,
    ];
    for (const v of received) {
      expect(isNull(v)).toBeTruthy();
    }
  });
});最后更新于
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